#!/usr/bin/env python3 """Exact utility-dominant collapse, including Markov memory. Tail optimization, collision-envelope certificates, and an exact arithmetic inverse-CDF generator. Every validity calculation uses fractions. The random bit generator in tests is reproducible, not cryptographic. """ from __future__ import annotations from fractions import Fraction as F from bisect import bisect_right from dataclasses import dataclass from certified_compiler import rational,Task,BitSource,pack_fraction @dataclass(frozen=True) class MarkovSource: initial:tuple[F,...] transition:tuple[tuple[F,...],...] useful:tuple[int,...] def __post_init__(self): pi=tuple(rational(v) for v in self.initial) P=tuple(tuple(rational(v) for v in row) for row in self.transition) h=tuple(self.useful) d=len(pi) if d<2 or min(pi)<=0 or sum(pi)!=1 or len(P)!=d or any(len(row)!=d or min(row)<=0 or sum(row)!=1 for row in P): raise ValueError('Full-support initial vector and stochastic transition matrix required.') if len(h)!=d or any(isinstance(v,bool) or not isinstance(v,int) or v not in (0,1) for v in h) or not 0= target. Returns a scalar-count acceptance rule and an exact source-only LP dual. The source can be arbitrary: only its exact count distribution is used. """ p=tuple(rational(v) for v in probabilities);t=rational(target) n=len(p)-1 if n<1 or min(p)<0 or sum(p)!=1 or not 0<=t<=n: raise ValueError('Invalid count distribution or target.') if sum((j*v for j,v in enumerate(p)),F(0))>=t: return {'acceptance':tuple(F(1) for _ in p),'mass':F(1),'cut':None,'fraction':F(1),'eta_count':F(0),'target_count':t} acceptance=[F(0) for _ in p] slack=F(0) eta=None;cut=None;fraction=None for j in reversed(range(n+1)): b=F(j)-t if b<0 and slack+b*p[j]<0: fraction=slack/(-b*p[j]) acceptance[j]=fraction eta=1/(-b);cut=j break acceptance[j]=1 slack+=b*p[j] if eta is None:raise ArithmeticError('Tail boundary not found.') mass=sum((v*a for v,a in zip(p,acceptance)),F(0)) utility=sum((v*a*(j-t) for j,(v,a) in enumerate(zip(p,acceptance))),F(0)) dual=sum((v*max(F(0),1+eta*(j-t)) for j,v in enumerate(p)),F(0)) if utility!=0 or mass!=dual:raise ArithmeticError('Tail primal/dual equality failed.') return {'acceptance':tuple(acceptance),'mass':mass,'cut':cut,'fraction':fraction,'eta_count':eta,'target_count':t} def envelope_constant(acceptance,z): z=rational(z) if z<1:raise ValueError('Tilt z >= 1 required.') return max((rational(a)/z**j for j,a in enumerate(acceptance)),default=F(0)) def tilted_collision(source:MarkovSource,task:Task,n:int,z): """Exact b^n times squared output mass of mu(w) z^J(w). Synchronized pair recursion, using P^T V P in O(n d^3) arithmetic. This includes temporal dependencies, not just one-letter marginals. """ z=rational(z);d=source.d;P=source.transition;h=source.useful if len(task.mapping)!=d or n<1 or z<=0:raise ValueError('Invalid collision parameters.') V=[[source.initial[a]*source.initial[b]*z**(h[a]+h[b]) if task.mapping[a]==task.mapping[b] else F(0) for b in range(d)] for a in range(d)] for _ in range(n-1): W=[[sum((V[a][b]*P[b][e] for b in range(d)),F(0)) for e in range(d)] for a in range(d)] V=[[z**(h[c]+h[e])*sum((P[a][c]*W[a][e] for a in range(d)),F(0)) if task.mapping[c]==task.mapping[e] else F(0) for e in range(d)] for c in range(d)] return task.base**n*sum((sum(row,F(0)) for row in V),F(0)) def collapse_certificate(source:MarkovSource,tasks,n:int,threshold,z=F(5)): gamma=rational(threshold);z=rational(z) if not 0<=gamma<=1:raise ValueError('Frequency threshold in [0,1] required.') counts=count_law(source,n) tail=optimal_tail(counts,n*gamma) C=envelope_constant(tail['acceptance'],z) bounds=tuple(C*C*tilted_collision(source,t,n,z) for t in tasks) return {'depth':n,'threshold':gamma,'count_law':counts,**tail,'tilt':z,'envelope_constant':C, 'collision_upper_bounds':bounds,'collapse_proved':all(v<=1 for v in bounds), 'optimal_expected_source_proposals':1/tail['mass'] if tail['mass'] else None} class TailGenerator: """Finite-horizon Doob/conditional generator plus exact interval decoding. After O(n^2 d^2) exact arithmetic preprocessing, the emitted word law is Q(w) = mu(w) a[J(w)] / M. It consumes at most H_2(Q)+3 bits in expectation. That bound is an established interval-sampling principle, not a new code. Normalized Q does NOT automatically satisfy the original mass-one L2 bound. """ def __init__(self,source:MarkovSource,n:int,acceptance): self.source=source;self.n=n self.acceptance=tuple(rational(v) for v in acceptance) if isinstance(n,bool) or not isinstance(n,int) or n<1 or len(self.acceptance)!=n+1 or any(not 0<=v<=1 for v in self.acceptance): raise ValueError('Invalid horizon or acceptance vector.') d=source.d # H[i][j][a] = expected terminal acceptance with i positions seen, # current useful count j, and current state a. All 0<=j<=i included. H=[None]*(n+1) H[n]=[[self.acceptance[j] for _ in range(d)] for j in range(n+1)] for i in reversed(range(1,n)): H[i]=[[sum((source.transition[a][b]*H[i+1][j+source.useful[b]][b] for b in range(d)),F(0)) for a in range(d)] for j in range(i+1)] self.H=H self.mass=sum((source.initial[a]*H[1][source.useful[a]][a] for a in range(d)),F(0)) if self.mass<=0:raise ValueError('Accepted law has zero mass.') def conditional(self,prefix): i=len(prefix);s=self.source if not 0<=i