content: #  Copyright (c) ZenML GmbH 2022. All Rights Reserved.
  #
  #  Licensed under the Apache License, Version 2.0 (the "License");
  #  you may not use this file except in compliance with the License.
  #  You may obtain a copy of the License at:
  #
  #       https://www.apache.org/licenses/LICENSE-2.0
  #
  #  Unless required by applicable law or agreed to in writing, software
  #  distributed under the License is distributed on an "AS IS" BASIS,
  #  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express
  #  or implied. See the License for the specific language governing
  #  permissions and limitations under the License.
  """Utility methods for S3."""
  
  from typing import Tuple
  
  
  def split_s3_path(s3_path: str) -> Tuple[str, str]:
      """Split S3 URI into bucket and key.
  
      Args:
          s3_path: S3 URI (e.g. "s3://bucket/path")
  
      Returns:
          A tuple of bucket and key, for "s3://bucket/path/path2"
              it will return ("bucket","path/path2")
  
      Raises:
          ValueError: if the S3 URI is invalid
      """
      if not s3_path.startswith("s3://"):
          raise ValueError(
              f"Invalid S3 URI given: {s3_path}. It should start with `s3://`."
          )
      path_parts = s3_path.replace("s3://", "").split("/")
      bucket = path_parts.pop(0)
      key = "/".join(path_parts)
      return bucket, key
  