The number of public highschool in Evervale City equals the total number of schools in Hawkesbury. The number of regional medical school in Hawkesbury equals 2. The number of culinarian school in Brightford equals the number of regional medical school in Hawkesbury. The number of culinarian school in Evervale City equals 1 plus the total number of schools in Brightford. The number of culinarian school in Hawkesbury equals 4. The number of regional medical school in Brightford equals 4 times the number of regional medical school in Hawkesbury. The number of public highschool in Brightford equals the difference between the number of public highschool in Evervale City and the number of regional medical school in Hawkesbury.

Question: How many culinarian school does Evervale City have?

Solution: Define culinarian school in Hawkesbury as b; so b = 4. Define regional medical school in Hawkesbury as O; so O = 2. Define total number of schools in Hawkesbury as S; so S = O + b = 2 + 4 = 6. Define public highschool in Evervale City as T; so T = S = 6. Define regional medical school in Brightford as C; R = O = 2; so C = 4 * R = 4 * 2 = 8. Define public highschool in Brightford as G; so G = T - O = 6 - 2 = 4. Define culinarian school in Brightford as q; so q = O = 2. Define total number of schools in Brightford as g; B = C + q = 8 + 2 = 10; so g = B + G = 10 + 4 = 14. Define culinarian school in Evervale City as o; y = g = 14; so o = 1 + y = 1 + 14 = 15. Answer: 15.


The number of private middle school in Shoreline City equals the number of culinarian school in Shoreline City. The number of culinarian school in Oakbridge City equals 3 times the number of private middle school in Shoreline City. The number of public highschool in Ruby Bay equals the number of regional medical school in Shoreline City. The number of culinarian school in Clearwater Bay equals 1 plus the number of private middle school in Shoreline City. The number of public highschool in Clearwater Bay equals the number of culinarian school in Ruby Bay. The number of culinarian school in Shoreline City equals 1. The number of private middle school in Oakbridge City equals 2. The number of public highschool in Oakbridge City equals the number of regional medical school in Ruby Bay. The number of regional medical school in Ruby Bay equals 1. The number of public highschool in Shoreline City equals 4 times the number of culinarian school in Shoreline City. The number of culinarian school in Ruby Bay equals the total number of schools in Shoreline City. The number of private middle school in Ruby Bay equals 2. The number of regional medical school in Shoreline City equals the number of private middle school in Shoreline City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define culinarian school in Shoreline City as f; so f = 1. Define public highschool in Shoreline City as y; O = f = 1; so y = 4 * O = 4 * 1 = 4. Define private middle school in Shoreline City as J; so J = f = 1. Define regional medical school in Shoreline City as N; so N = J = 1. Define total number of schools in Shoreline City as U; e = y + f = 4 + 1 = 5; j = e + J = 5 + 1 = 6; so U = j + N = 6 + 1 = 7. Define culinarian school in Ruby Bay as v; so v = U = 7. Define culinarian school in Clearwater Bay as W; b = J = 1; so W = 1 + b = 1 + 1 = 2. Define public highschool in Clearwater Bay as w; so w = v = 7. Define total number of schools in Clearwater Bay as L; so L = w + W = 7 + 2 = 9. Answer: 9.


The number of adult eagle in Beverly Forest equals 3. The number of adult blue jay in Oakridge Riverside equals 3. The number of adult crow in Maple Creek equals 4 plus the number of adult eagle in Beverly Forest. The number of adult parrot in Beverly Forest equals 3. The number of adult parrot in Maple Creek equals 3 plus the number of adult crow in Maple Creek. The number of adult eagle in Oakridge Riverside equals 2 plus the sum of the total number of adult animals in Maple Creek, the number of adult blue jay in Oakridge Riverside, and the number of adult parrot in Maple Creek. The number of adult blue jay in Beverly Forest equals the difference between the total number of adult animals in Maple Creek and the number of adult eagle in Beverly Forest. The number of adult crow in Oakridge Riverside equals the number of adult blue jay in Pine Ridge. The number of adult eagle in Maple Creek equals the number of adult crow in Maple Creek. The number of adult crow in Beverly Forest equals 2 times the sum of the number of adult parrot in Maple Creek, the number of adult eagle in Beverly Forest, and the number of adult crow in Maple Creek. The number of adult parrot in Oakridge Riverside equals 2. The number of adult blue jay in Pine Ridge equals the number of adult parrot in Beverly Forest. The number of adult crow in Pine Ridge equals the number of adult crow in Oakridge Riverside. The number of adult blue jay in Maple Creek equals the number of adult crow in Beverly Forest.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult eagle in Beverly Forest as V; so V = 3. Define adult crow in Maple Creek as a; y = V = 3; so a = 4 + y = 4 + 3 = 7. Define adult parrot in Maple Creek as o; Y = a = 7; so o = 3 + Y = 3 + 7 = 10. Define adult crow in Beverly Forest as p; U = o + V = 10 + 3 = 13; r = U + a = 13 + 7 = 20; so p = 2 * r = 2 * 20 = 40. Define adult eagle in Maple Creek as q; so q = a = 7. Define adult blue jay in Maple Creek as G; so G = p = 40. Define total number of adult animals in Maple Creek as g; C = q + o = 7 + 10 = 17; J = C + G = 17 + 40 = 57; so g = J + a = 57 + 7 = 64. Answer: 64.


The number of adult fox in Hamilton Farm equals 1 plus the number of adult deer in Hamilton Farm. The number of adult wolf in Jefferson Circus equals the sum of the number of adult deer in Hamilton Farm, the number of adult deer in Jefferson Circus, the number of adult fox in Hamilton Farm, and the total number of adult animals in Hamilton Farm. The number of adult wolf in South Zoo equals the number of adult deer in South Zoo. The number of adult fox in Jefferson Circus equals 1 plus the total number of adult animals in Hamilton Farm. The number of adult deer in Jefferson Circus equals 4. The number of adult fox in South Zoo equals the sum of the number of adult fox in Hamilton Farm and the number of adult fox in Jefferson Circus. The number of adult deer in Hamilton Farm equals 3. The number of adult deer in South Zoo equals 3.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult deer in Hamilton Farm as C; so C = 3. Define adult fox in Hamilton Farm as i; E = C = 3; so i = 1 + E = 1 + 3 = 4. Define adult deer in Jefferson Circus as b; so b = 4. Define total number of adult animals in Hamilton Farm as N; so N = C + i = 3 + 4 = 7. Define adult wolf in Jefferson Circus as y; k = C + b = 3 + 4 = 7; G = k + i = 7 + 4 = 11; so y = G + N = 11 + 7 = 18. Define adult fox in Jefferson Circus as w; n = N = 7; so w = 1 + n = 1 + 7 = 8. Define total number of adult animals in Jefferson Circus as u; d = y + w = 18 + 8 = 26; so u = d + b = 26 + 4 = 30. Answer: 30.


The number of culinarian school in Ruby Bay equals the sum of the total number of schools in Clearwater Bay and the number of culinarian school in Clearwater Bay. The number of elementary school in Oakbridge City equals the sum of the total number of schools in Ruby Bay, the total number of schools in Clearwater Bay, and the number of culinarian school in Ruby Bay. The number of regional medical school in Oakbridge City equals the total number of schools in Shoreline City. The number of private middle school in Ruby Bay equals 1 plus the number of culinarian school in Ruby Bay. The number of regional medical school in Shoreline City equals 4. The number of culinarian school in Clearwater Bay equals 2 plus the number of regional medical school in Oakbridge City.

Question: How many elementary school does Oakbridge City have?

Solution: Define regional medical school in Shoreline City as x; so x = 4. Define total number of schools in Shoreline City as h; so h = x = 4. Define regional medical school in Oakbridge City as y; so y = h = 4. Define culinarian school in Clearwater Bay as S; H = y = 4; so S = 2 + H = 2 + 4 = 6. Define total number of schools in Clearwater Bay as J; so J = S = 6. Define culinarian school in Ruby Bay as T; so T = J + S = 6 + 6 = 12. Define private middle school in Ruby Bay as t; v = T = 12; so t = 1 + v = 1 + 12 = 13. Define total number of schools in Ruby Bay as g; so g = t + T = 13 + 12 = 25. Define elementary school in Oakbridge City as Z; V = g + J = 25 + 6 = 31; so Z = V + T = 31 + 12 = 43. Answer: 43.


The number of adult fox in Oakridge Riverside equals the number of adult deer in Oakridge Riverside. The number of adult deer in Cedar Valley equals 4 plus the total number of adult animals in Oakridge Riverside. The number of adult deer in Beverly Forest equals the number of adult deer in Cedar Valley. The number of adult fox in Beverly Forest equals 2. The number of adult wolf in Oakridge Riverside equals 3. The number of adult wolf in Beverly Forest equals 2 times the number of adult deer in Beverly Forest. The number of adult fox in Cedar Valley equals the total number of adult animals in Beverly Forest. The number of adult deer in Oakridge Riverside equals 3. The number of adult wolf in Cedar Valley equals the sum of the number of adult deer in Oakridge Riverside, the number of adult fox in Oakridge Riverside, the number of adult deer in Cedar Valley, and the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult deer in Oakridge Riverside as M; so M = 3. Define adult fox in Oakridge Riverside as o; so o = M = 3. Define adult wolf in Oakridge Riverside as x; so x = 3. Define total number of adult animals in Oakridge Riverside as R; T = x + M = 3 + 3 = 6; so R = T + o = 6 + 3 = 9. Define adult deer in Cedar Valley as m; V = R = 9; so m = 4 + V = 4 + 9 = 13. Define adult deer in Beverly Forest as X; so X = m = 13. Define adult wolf in Beverly Forest as I; h = X = 13; so I = 2 * h = 2 * 13 = 26. Define adult fox in Beverly Forest as a; so a = 2. Define total number of adult animals in Beverly Forest as v; r = I + X = 26 + 13 = 39; so v = r + a = 39 + 2 = 41. Answer: 41.


The number of private middle school in Hawkesbury equals the total number of schools in Westhaven City. The number of elementary school in Brightford equals 3 times the number of regional medical school in Westhaven City. The number of elementary school in Hawkesbury equals 3 times the number of private middle school in Hawkesbury. The number of private middle school in Westhaven City equals 2. The number of private middle school in Brightford equals the number of elementary school in Hawkesbury. The number of regional medical school in Hawkesbury equals the total number of schools in Brightford. The number of regional medical school in Westhaven City equals the number of private middle school in Westhaven City. The number of elementary school in Westhaven City equals 4.

Question: How many regional medical school does Hawkesbury have?

Solution: Define private middle school in Westhaven City as x; so x = 2. Define regional medical school in Westhaven City as c; so c = x = 2. Define elementary school in Westhaven City as a; so a = 4. Define total number of schools in Westhaven City as D; K = x + a = 2 + 4 = 6; so D = K + c = 6 + 2 = 8. Define private middle school in Hawkesbury as T; so T = D = 8. Define elementary school in Hawkesbury as v; Z = T = 8; so v = 3 * Z = 3 * 8 = 24. Define private middle school in Brightford as e; so e = v = 24. Define elementary school in Brightford as w; m = c = 2; so w = 3 * m = 3 * 2 = 6. Define total number of schools in Brightford as h; so h = e + w = 24 + 6 = 30. Define regional medical school in Hawkesbury as r; so r = h = 30. Answer: 30.


The number of adult eagle in Beverly Forest equals the number of adult parrot in Maple Creek. The number of adult parrot in Pine Ridge equals 4. The number of adult blue jay in Cedar Valley equals 2 times the difference between the number of adult crow in Cedar Valley and the number of adult owl in Pine Ridge. The number of adult crow in Beverly Forest equals 2 plus the number of adult blue jay in Oakridge Riverside. The number of adult parrot in Maple Creek equals 4. The number of adult crow in Cedar Valley equals the sum of the number of adult owl in Cedar Valley, the number of adult crow in Oakridge Riverside, and the number of adult owl in Pine Ridge. The number of adult crow in Oakridge Riverside equals 2 times the number of adult parrot in Maple Creek. The number of adult crow in Pine Ridge equals the number of adult eagle in Pine Ridge. The number of adult eagle in Oakridge Riverside equals the sum of the number of adult crow in Oakridge Riverside and the number of adult blue jay in Cedar Valley. The number of adult owl in Cedar Valley equals 1 plus the sum of the number of adult owl in Pine Ridge, the number of adult parrot in Maple Creek, and the number of adult crow in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 4. The number of adult eagle in Pine Ridge equals the number of adult blue jay in Oakridge Riverside. The number of adult owl in Pine Ridge equals 4 times the number of adult crow in Oakridge Riverside. The number of adult owl in Maple Creek equals 3 plus the sum of the number of adult crow in Oakridge Riverside, the number of adult crow in Cedar Valley, and the number of adult owl in Pine Ridge. The number of adult parrot in Oakridge Riverside equals the number of adult crow in Beverly Forest. The number of adult blue jay in Pine Ridge equals 2.

Question: How many adult blue jay does Cedar Valley have?

Solution: Define adult parrot in Maple Creek as F; so F = 4. Define adult crow in Oakridge Riverside as P; o = F = 4; so P = 2 * o = 2 * 4 = 8. Define adult owl in Pine Ridge as V; b = P = 8; so V = 4 * b = 4 * 8 = 32. Define adult owl in Cedar Valley as K; M = V + F = 32 + 4 = 36; d = M + P = 36 + 8 = 44; so K = 1 + d = 1 + 44 = 45. Define adult crow in Cedar Valley as Q; B = K + P = 45 + 8 = 53; so Q = B + V = 53 + 32 = 85. Define adult blue jay in Cedar Valley as R; T = Q - V = 85 - 32 = 53; so R = 2 * T = 2 * 53 = 106. Answer: 106.


The number of adult racoon in Hamilton Farm equals the sum of the total number of adult animals in Mayer Aquarium and the number of adult wolf in Mayer Aquarium. The number of adult fox in Hamilton Farm equals the difference between the number of adult racoon in Hamilton Farm and the total number of adult animals in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals the total number of adult animals in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the number of adult racoon in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 3. The number of adult fox in Jefferson Circus equals 1 plus the number of adult racoon in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult racoon in Jefferson Circus as S; so S = 3. Define adult fox in Jefferson Circus as O; R = S = 3; so O = 1 + R = 1 + 3 = 4. Define adult wolf in Jefferson Circus as h; so h = S = 3. Define total number of adult animals in Jefferson Circus as L; Y = h + S = 3 + 3 = 6; so L = Y + O = 6 + 4 = 10. Define adult wolf in Mayer Aquarium as I; so I = L = 10. Define total number of adult animals in Mayer Aquarium as C; so C = I = 10. Define adult racoon in Hamilton Farm as k; so k = C + I = 10 + 10 = 20. Define adult fox in Hamilton Farm as Z; so Z = k - L = 20 - 10 = 10. Define total number of adult animals in Hamilton Farm as a; so a = k + Z = 20 + 10 = 30. Answer: 30.


The number of private middle school in Hawkesbury equals the sum of the number of elementary school in Glenfield City and the number of private middle school in Glenfield City. The number of culinarian school in Hawkesbury equals the number of private middle school in Hawkesbury. The number of elementary school in Hawkesbury equals 4. The number of private middle school in Evervale City equals the number of culinarian school in Evervale City. The number of culinarian school in Glenfield City equals 2. The number of culinarian school in Evervale City equals 2 times the number of private middle school in Glenfield City. The number of private middle school in Glenfield City equals 3. The number of elementary school in Glenfield City equals 2 plus the total number of schools in Evervale City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Glenfield City as d; so d = 3. Define culinarian school in Evervale City as i; f = d = 3; so i = 2 * f = 2 * 3 = 6. Define private middle school in Evervale City as e; so e = i = 6. Define total number of schools in Evervale City as b; so b = e + i = 6 + 6 = 12. Define elementary school in Glenfield City as y; p = b = 12; so y = 2 + p = 2 + 12 = 14. Define private middle school in Hawkesbury as W; so W = y + d = 14 + 3 = 17. Define culinarian school in Hawkesbury as X; so X = W = 17. Define elementary school in Hawkesbury as x; so x = 4. Define total number of schools in Hawkesbury as G; v = W + X = 17 + 17 = 34; so G = v + x = 34 + 4 = 38. Answer: 38.


The number of adult blue jay in Pine Ridge equals 4 times the number of adult eagle in Beverly Forest. The number of adult blue jay in Oakridge Riverside equals 3. The number of adult crow in Beverly Forest equals 2. The number of adult owl in Beverly Forest equals 4 plus the sum of the total number of adult animals in Cedar Valley, the number of adult blue jay in Oakridge Riverside, and the number of adult blue jay in Pine Ridge. The number of adult eagle in Beverly Forest equals 1 plus the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Maple Creek equals the number of adult owl in Beverly Forest. The number of adult parrot in Cedar Valley equals the difference between the total number of adult animals in Pine Ridge and the number of adult eagle in Beverly Forest.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult blue jay in Oakridge Riverside as W; so W = 3. Define adult eagle in Beverly Forest as D; v = W = 3; so D = 1 + v = 1 + 3 = 4. Define adult blue jay in Pine Ridge as u; l = D = 4; so u = 4 * l = 4 * 4 = 16. Define total number of adult animals in Pine Ridge as s; so s = u = 16. Define adult parrot in Cedar Valley as I; so I = s - D = 16 - 4 = 12. Define total number of adult animals in Cedar Valley as j; so j = I = 12. Define adult owl in Beverly Forest as O; k = j + W = 12 + 3 = 15; E = k + u = 15 + 16 = 31; so O = 4 + E = 4 + 31 = 35. Define adult blue jay in Maple Creek as g; so g = O = 35. Define total number of adult animals in Maple Creek as c; so c = g = 35. Answer: 35.


The number of adult deer in Jefferson Circus equals the number of adult deer in Bundle Ranch. The number of adult wolf in Jefferson Circus equals 4 times the total number of adult animals in Bundle Ranch. The number of adult fox in Jefferson Circus equals 2. The number of adult deer in Bundle Ranch equals 1 plus the sum of the total number of adult animals in South Zoo and the number of adult bear in South Zoo. The number of adult bear in Bundle Ranch equals the number of adult bear in South Zoo. The number of adult bear in South Zoo equals 1.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult bear in South Zoo as t; so t = 1. Define total number of adult animals in South Zoo as C; so C = t = 1. Define adult bear in Bundle Ranch as s; so s = t = 1. Define adult deer in Bundle Ranch as Q; d = C + t = 1 + 1 = 2; so Q = 1 + d = 1 + 2 = 3. Define total number of adult animals in Bundle Ranch as A; so A = Q + s = 3 + 1 = 4. Define adult wolf in Jefferson Circus as p; E = A = 4; so p = 4 * E = 4 * 4 = 16. Define adult fox in Jefferson Circus as K; so K = 2. Define adult deer in Jefferson Circus as G; so G = Q = 3. Define total number of adult animals in Jefferson Circus as M; v = K + G = 2 + 3 = 5; so M = v + p = 5 + 16 = 21. Answer: 21.


The number of adult bear in Maple Creek equals the total number of adult animals in Maple Creek. The number of adult bear in Oakridge Riverside equals 3. The number of adult racoon in Oakridge Riverside equals 4. The number of adult wolf in Oakridge Riverside equals the number of adult wolf in Maple Creek. The number of adult racoon in Pine Ridge equals 3. The number of adult deer in Pine Ridge equals the number of adult deer in Maple Creek. The number of adult wolf in Maple Creek equals 4 plus the number of adult wolf in Pine Ridge. The number of adult bear in Pine Ridge equals 4 times the number of adult wolf in Maple Creek. The number of adult deer in Maple Creek equals 2. The number of adult deer in Oakridge Riverside equals the sum of the number of adult bear in Pine Ridge, the number of adult wolf in Maple Creek, and the number of adult wolf in Pine Ridge. The number of adult wolf in Pine Ridge equals 4.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult wolf in Pine Ridge as k; so k = 4. Define adult wolf in Maple Creek as T; L = k = 4; so T = 4 + L = 4 + 4 = 8. Define adult bear in Pine Ridge as g; B = T = 8; so g = 4 * B = 4 * 8 = 32. Define adult deer in Oakridge Riverside as Z; v = g + T = 32 + 8 = 40; so Z = v + k = 40 + 4 = 44. Define adult wolf in Oakridge Riverside as N; so N = T = 8. Define adult bear in Oakridge Riverside as D; so D = 3. Define adult racoon in Oakridge Riverside as Q; so Q = 4. Define total number of adult animals in Oakridge Riverside as o; t = N + D = 8 + 3 = 11; R = t + Q = 11 + 4 = 15; so o = R + Z = 15 + 44 = 59. Answer: 59.


The number of private middle school in Brightford equals 2. The number of public highschool in Westhaven City equals the number of public highschool in Brightford. The number of private middle school in Glenfield City equals the difference between the total number of schools in Westhaven City and the number of public highschool in Brightford. The number of private middle school in Evervale City equals 2 plus the total number of schools in Glenfield City. The number of public highschool in Evervale City equals the sum of the number of private middle school in Evervale City, the number of private middle school in Glenfield City, and the number of private middle school in Westhaven City. The number of private middle school in Westhaven City equals 3. The number of public highschool in Brightford equals 3.

Question: What is the total number of schools in Evervale City?

Solution: Define public highschool in Brightford as I; so I = 3. Define public highschool in Westhaven City as j; so j = I = 3. Define private middle school in Westhaven City as a; so a = 3. Define total number of schools in Westhaven City as B; so B = j + a = 3 + 3 = 6. Define private middle school in Glenfield City as v; so v = B - I = 6 - 3 = 3. Define total number of schools in Glenfield City as Z; so Z = v = 3. Define private middle school in Evervale City as c; X = Z = 3; so c = 2 + X = 2 + 3 = 5. Define public highschool in Evervale City as K; J = c + v = 5 + 3 = 8; so K = J + a = 8 + 3 = 11. Define total number of schools in Evervale City as p; so p = K + c = 11 + 5 = 16. Answer: 16.


The number of public highschool in Westhaven City equals the sum of the total number of schools in Hawkesbury, the number of public highschool in Hawkesbury, and the number of regional medical school in Evervale City. The number of public highschool in Hawkesbury equals the difference between the total number of schools in Evervale City and the number of public highschool in Evervale City. The number of regional medical school in Westhaven City equals 1. The number of regional medical school in Evervale City equals 2. The number of regional medical school in Hawkesbury equals 3. The number of public highschool in Evervale City equals 2.

Question: What is the total number of schools in Westhaven City?

Solution: Define regional medical school in Evervale City as k; so k = 2. Define public highschool in Evervale City as o; so o = 2. Define total number of schools in Evervale City as Y; so Y = o + k = 2 + 2 = 4. Define public highschool in Hawkesbury as u; so u = Y - o = 4 - 2 = 2. Define regional medical school in Hawkesbury as f; so f = 3. Define total number of schools in Hawkesbury as G; so G = u + f = 2 + 3 = 5. Define public highschool in Westhaven City as K; a = G + u = 5 + 2 = 7; so K = a + k = 7 + 2 = 9. Define regional medical school in Westhaven City as d; so d = 1. Define total number of schools in Westhaven City as J; so J = K + d = 9 + 1 = 10. Answer: 10.


The number of intense detective thriller in Taylor Movie Festival equals 3 plus the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of calm road movie in Verdi Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of calm road movie in Verdi Movie Festival equals 2 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 3.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define futuristic sci-fi movie in Verdi Movie Festival as q; so q = 4. Define calm road movie in Verdi Movie Festival as Y; d = q = 4; so Y = 2 * d = 2 * 4 = 8. Define total number of movies in Verdi Movie Festival as o; so o = q + Y = 4 + 8 = 12. Define futuristic sci-fi movie in West Sahara Movie Festival as U; c = o + Y = 12 + 8 = 20; so U = c + q = 20 + 4 = 24. Define total number of movies in West Sahara Movie Festival as j; so j = U = 24. Define intense detective thriller in Taylor Movie Festival as e; y = j - Y = 24 - 8 = 16; so e = 3 + y = 3 + 16 = 19. Define futuristic sci-fi movie in Taylor Movie Festival as g; so g = 3. Define total number of movies in Taylor Movie Festival as V; so V = e + g = 19 + 3 = 22. Answer: 22.


The number of adult crow in Beverly Forest equals 3. The number of adult crow in Oakridge Riverside equals 4 plus the difference between the number of adult owl in Oakridge Riverside and the number of adult crow in Beverly Forest. The number of adult owl in Oakridge Riverside equals 1 plus the sum of the total number of adult animals in Beverly Forest, the number of adult crow in Beverly Forest, and the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 4. The number of adult eagle in Beverly Forest equals the number of adult crow in Beverly Forest.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult crow in Beverly Forest as M; so M = 3. Define adult eagle in Beverly Forest as s; so s = M = 3. Define adult owl in Beverly Forest as r; so r = 4. Define total number of adult animals in Beverly Forest as Q; J = s + r = 3 + 4 = 7; so Q = J + M = 7 + 3 = 10. Define adult owl in Oakridge Riverside as b; u = Q + M = 10 + 3 = 13; S = u + r = 13 + 4 = 17; so b = 1 + S = 1 + 17 = 18. Define adult crow in Oakridge Riverside as N; G = b - M = 18 - 3 = 15; so N = 4 + G = 4 + 15 = 19. Define total number of adult animals in Oakridge Riverside as W; so W = b + N = 18 + 19 = 37. Answer: 37.


The number of adult crow in Hamilton Farm equals 3 plus the number of adult crow in Jefferson Circus. The number of adult crow in Jefferson Circus equals 4. The number of adult owl in Jefferson Circus equals 4. The number of adult owl in Mayer Aquarium equals 1 plus the difference between the number of adult crow in Hamilton Farm and the number of adult crow in Jefferson Circus. The number of adult parrot in Hamilton Farm equals 2. The number of adult crow in Mayer Aquarium equals the sum of the number of adult crow in Jefferson Circus and the number of adult crow in Hamilton Farm. The number of adult parrot in Jefferson Circus equals 4. The number of adult owl in Hamilton Farm equals 2 plus the number of adult parrot in Mayer Aquarium. The number of adult parrot in Mayer Aquarium equals 4 plus the sum of the number of adult crow in Mayer Aquarium, the number of adult crow in Jefferson Circus, and the number of adult crow in Hamilton Farm.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult crow in Jefferson Circus as K; so K = 4. Define adult crow in Hamilton Farm as m; b = K = 4; so m = 3 + b = 3 + 4 = 7. Define adult owl in Mayer Aquarium as T; C = m - K = 7 - 4 = 3; so T = 1 + C = 1 + 3 = 4. Define adult crow in Mayer Aquarium as i; so i = K + m = 4 + 7 = 11. Define adult parrot in Mayer Aquarium as p; j = i + K = 11 + 4 = 15; N = j + m = 15 + 7 = 22; so p = 4 + N = 4 + 22 = 26. Define total number of adult animals in Mayer Aquarium as w; H = T + p = 4 + 26 = 30; so w = H + i = 30 + 11 = 41. Answer: 41.


The number of calm road movie in West Sahara Movie Festival equals 4 times the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the total number of movies in West Sahara Movie Festival. The number of calm road movie in Northwood Movie Festival equals the sum of the number of calm road movie in West Sahara Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the total number of movies in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the total number of movies in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4.

Question: How many futuristic sci-fi movie does Northwood Movie Festival have?

Solution: Define futuristic sci-fi movie in West Sahara Movie Festival as A; so A = 4. Define solemn period drama in West Sahara Movie Festival as p; so p = A = 4. Define calm road movie in West Sahara Movie Festival as b; h = A = 4; so b = 4 * h = 4 * 4 = 16. Define total number of movies in West Sahara Movie Festival as c; k = b + p = 16 + 4 = 20; so c = k + A = 20 + 4 = 24. Define solemn period drama in Golden Banana Movie Festival as Y; so Y = c = 24. Define futuristic sci-fi movie in Golden Banana Movie Festival as O; so O = c = 24. Define calm road movie in Golden Banana Movie Festival as S; so S = p = 4. Define total number of movies in Golden Banana Movie Festival as N; q = O + Y = 24 + 24 = 48; so N = q + S = 48 + 4 = 52. Define futuristic sci-fi movie in Northwood Movie Festival as G; I = N = 52; so G = 2 + I = 2 + 52 = 54. Answer: 54.


The number of adult blue jay in South Zoo equals the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 2. The number of adult eagle in Jefferson Circus equals the sum of the number of adult blue jay in Jefferson Circus and the number of adult blue jay in South Zoo. The number of adult owl in Hamilton Farm equals the sum of the number of adult eagle in South Zoo, the number of adult blue jay in South Zoo, and the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Jefferson Circus equals 4 times the number of adult owl in Hamilton Farm. The number of adult eagle in South Zoo equals 4 times the number of adult blue jay in South Zoo. The number of adult owl in South Zoo equals 3 plus the total number of adult animals in Jefferson Circus.

Question: How many adult owl does South Zoo have?

Solution: Define adult blue jay in Hamilton Farm as Y; so Y = 2. Define adult blue jay in South Zoo as P; so P = Y = 2. Define adult eagle in South Zoo as V; k = P = 2; so V = 4 * k = 4 * 2 = 8. Define adult owl in Hamilton Farm as d; L = V + P = 8 + 2 = 10; so d = L + Y = 10 + 2 = 12. Define adult blue jay in Jefferson Circus as N; M = d = 12; so N = 4 * M = 4 * 12 = 48. Define adult eagle in Jefferson Circus as G; so G = N + P = 48 + 2 = 50. Define total number of adult animals in Jefferson Circus as z; so z = N + G = 48 + 50 = 98. Define adult owl in South Zoo as Q; a = z = 98; so Q = 3 + a = 3 + 98 = 101. Answer: 101.