The number of elementary school in Oakbridge City equals 4 plus the sum of the total number of schools in Riverton City, the number of elementary school in Riverton City, and the number of public highschool in Riverton City. The number of elementary school in Riverton City equals 1. The number of public highschool in Riverton City equals 4 plus the number of elementary school in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define elementary school in Riverton City as d; so d = 1. Define public highschool in Riverton City as w; q = d = 1; so w = 4 + q = 4 + 1 = 5. Define total number of schools in Riverton City as z; so z = w + d = 5 + 1 = 6. Define elementary school in Oakbridge City as G; Q = z + d = 6 + 1 = 7; e = Q + w = 7 + 5 = 12; so G = 4 + e = 4 + 12 = 16. Define total number of schools in Oakbridge City as E; so E = G = 16. Answer: 16.


The number of solemn period drama in Festival de Clairmont equals the sum of the total number of movies in Festival de Saint-Rivage, the number of intense detective thriller in Festival de Saint-Rivage, and the number of solemn period drama in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Saint-Rivage equals the number of solemn period drama in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of intense detective thriller in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival de Saint-Rivage equals 4 times the number of intense detective thriller in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumière de Valmont equals 2.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Festival Lumière de Valmont as i; so i = 2. Define intense detective thriller in Festival de Saint-Rivage as g; so g = i = 2. Define calm road movie in Festival de Saint-Rivage as M; n = g = 2; so M = 4 * n = 4 * 2 = 8. Define total number of movies in Festival de Saint-Rivage as y; so y = g + M = 2 + 8 = 10. Define solemn period drama in Festival de Clairmont as Y; h = y + g = 10 + 2 = 12; so Y = h + i = 12 + 2 = 14. Define total number of movies in Festival de Clairmont as k; so k = Y = 14. Answer: 14.


The number of intense detective thriller in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Rêves de Belleville equals 2 times the difference between the total number of movies in Festival de Saint-Rivage and the number of intense detective thriller in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Rêves de Belleville equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Festival de Saint-Rivage as z; so z = 2. Define intense detective thriller in Festival de Saint-Rivage as g; so g = z = 2. Define total number of movies in Festival de Saint-Rivage as m; so m = g + z = 2 + 2 = 4. Define solemn period drama in Rêves de Belleville as S; h = m - g = 4 - 2 = 2; so S = 2 * h = 2 * 2 = 4. Define intense detective thriller in Rêves de Belleville as O; so O = 3. Define total number of movies in Rêves de Belleville as i; so i = O + S = 3 + 4 = 7. Answer: 7.


The number of adult racoon in Hamilton Farm equals 4. The number of adult deer in Mayer Aquarium equals the total number of adult animals in Hamilton Farm. The number of adult deer in Hamilton Farm equals the number of adult racoon in Hamilton Farm. The number of adult racoon in Mayer Aquarium equals the sum of the total number of adult animals in Hamilton Farm, the number of adult deer in Hamilton Farm, and the number of adult deer in Mayer Aquarium.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Hamilton Farm as w; so w = 4. Define adult deer in Hamilton Farm as E; so E = w = 4. Define total number of adult animals in Hamilton Farm as Z; so Z = w + E = 4 + 4 = 8. Define adult deer in Mayer Aquarium as e; so e = Z = 8. Define adult racoon in Mayer Aquarium as f; j = Z + E = 8 + 4 = 12; so f = j + e = 12 + 8 = 20. Define total number of adult animals in Mayer Aquarium as l; so l = f + e = 20 + 8 = 28. Answer: 28.


The number of private middle school in Westhaven City equals the number of culinarian school in Westhaven City. The number of private middle school in Glenfield City equals 2 times the sum of the total number of schools in Westhaven City, the number of private middle school in Westhaven City, and the number of culinarian school in Glenfield City. The number of culinarian school in Westhaven City equals 3 plus the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 2.

Question: How many private middle school does Glenfield City have?

Solution: Define culinarian school in Glenfield City as D; so D = 2. Define culinarian school in Westhaven City as t; Z = D = 2; so t = 3 + Z = 3 + 2 = 5. Define private middle school in Westhaven City as e; so e = t = 5. Define total number of schools in Westhaven City as o; so o = e + t = 5 + 5 = 10. Define private middle school in Glenfield City as W; s = o + e = 10 + 5 = 15; X = s + D = 15 + 2 = 17; so W = 2 * X = 2 * 17 = 34. Answer: 34.


The number of elementary school in Riverton City equals 1 plus the sum of the total number of schools in Oakbridge City and the number of elementary school in Oakbridge City. The number of public highschool in Riverton City equals the sum of the total number of schools in Oakbridge City, the number of elementary school in Oakbridge City, and the number of elementary school in Riverton City. The number of elementary school in Oakbridge City equals 3.

Question: What is the total number of schools in Riverton City?

Solution: Define elementary school in Oakbridge City as R; so R = 3. Define total number of schools in Oakbridge City as Y; so Y = R = 3. Define elementary school in Riverton City as J; G = Y + R = 3 + 3 = 6; so J = 1 + G = 1 + 6 = 7. Define public highschool in Riverton City as c; n = Y + R = 3 + 3 = 6; so c = n + J = 6 + 7 = 13. Define total number of schools in Riverton City as y; so y = J + c = 7 + 13 = 20. Answer: 20.


The number of culinarian school in Westhaven City equals 2 times the sum of the total number of schools in Glenfield City and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 2. The number of public highschool in Westhaven City equals 2. The number of public highschool in Glenfield City equals the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Westhaven City?

Solution: Define culinarian school in Glenfield City as O; so O = 2. Define public highschool in Glenfield City as s; so s = O = 2. Define total number of schools in Glenfield City as o; so o = s + O = 2 + 2 = 4. Define culinarian school in Westhaven City as Z; x = o + O = 4 + 2 = 6; so Z = 2 * x = 2 * 6 = 12. Define public highschool in Westhaven City as y; so y = 2. Define total number of schools in Westhaven City as m; so m = y + Z = 2 + 12 = 14. Answer: 14.


The number of adult blue jay in Mayer Aquarium equals the total number of adult animals in Hamilton Farm. The number of adult crow in South Zoo equals 4 times the difference between the total number of adult animals in Mayer Aquarium and the total number of adult animals in Hamilton Farm. The number of adult parrot in Mayer Aquarium equals the total number of adult animals in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 4.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult blue jay in Hamilton Farm as v; so v = 4. Define total number of adult animals in Hamilton Farm as D; so D = v = 4. Define adult parrot in Mayer Aquarium as f; so f = D = 4. Define adult blue jay in Mayer Aquarium as W; so W = D = 4. Define total number of adult animals in Mayer Aquarium as M; so M = W + f = 4 + 4 = 8. Define adult crow in South Zoo as o; T = M - D = 8 - 4 = 4; so o = 4 * T = 4 * 4 = 16. Define total number of adult animals in South Zoo as K; so K = o = 16. Answer: 16.


The number of adult fox in Jefferson Circus equals 2. The number of adult wolf in Jefferson Circus equals 1 plus the number of adult fox in Jefferson Circus. The number of adult wolf in Hamilton Farm equals the total number of adult animals in Jefferson Circus. The number of adult fox in Hamilton Farm equals 4 times the number of adult wolf in Hamilton Farm.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult fox in Jefferson Circus as Z; so Z = 2. Define adult wolf in Jefferson Circus as i; y = Z = 2; so i = 1 + y = 1 + 2 = 3. Define total number of adult animals in Jefferson Circus as Q; so Q = Z + i = 2 + 3 = 5. Define adult wolf in Hamilton Farm as W; so W = Q = 5. Define adult fox in Hamilton Farm as O; M = W = 5; so O = 4 * M = 4 * 5 = 20. Define total number of adult animals in Hamilton Farm as a; so a = O + W = 20 + 5 = 25. Answer: 25.


The number of culinarian school in Glenfield City equals 2. The number of elementary school in Glenfield City equals the number of culinarian school in Glenfield City. The number of elementary school in Brightford equals the total number of schools in Glenfield City. The number of culinarian school in Brightford equals the sum of the total number of schools in Glenfield City, the number of elementary school in Glenfield City, and the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Glenfield City as w; so w = 2. Define elementary school in Glenfield City as v; so v = w = 2. Define total number of schools in Glenfield City as n; so n = v + w = 2 + 2 = 4. Define culinarian school in Brightford as I; R = n + v = 4 + 2 = 6; so I = R + w = 6 + 2 = 8. Define elementary school in Brightford as g; so g = n = 4. Define total number of schools in Brightford as s; so s = g + I = 4 + 8 = 12. Answer: 12.


The number of culinarian school in Hawkesbury equals 3. The number of private middle school in Hawkesbury equals the number of culinarian school in Hawkesbury. The number of culinarian school in Westhaven City equals the sum of the total number of schools in Hawkesbury, the number of culinarian school in Hawkesbury, and the number of private middle school in Hawkesbury. The number of private middle school in Westhaven City equals the number of private middle school in Hawkesbury.

Question: What is the total number of schools in Westhaven City?

Solution: Define culinarian school in Hawkesbury as H; so H = 3. Define private middle school in Hawkesbury as f; so f = H = 3. Define total number of schools in Hawkesbury as F; so F = f + H = 3 + 3 = 6. Define private middle school in Westhaven City as n; so n = f = 3. Define culinarian school in Westhaven City as x; N = F + H = 6 + 3 = 9; so x = N + f = 9 + 3 = 12. Define total number of schools in Westhaven City as m; so m = n + x = 3 + 12 = 15. Answer: 15.


The number of public highschool in Clearwater Bay equals 4. The number of regional medical school in Oakbridge City equals 2. The number of public highschool in Shoreline City equals 3 plus the difference between the total number of schools in Oakbridge City and the number of regional medical school in Oakbridge City. The number of elementary school in Clearwater Bay equals the total number of schools in Shoreline City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define regional medical school in Oakbridge City as Z; so Z = 2. Define total number of schools in Oakbridge City as Q; so Q = Z = 2. Define public highschool in Shoreline City as q; R = Q - Z = 2 - 2 = 0; so q = 3 + R = 3 + 0 = 3. Define total number of schools in Shoreline City as T; so T = q = 3. Define elementary school in Clearwater Bay as H; so H = T = 3. Define public highschool in Clearwater Bay as W; so W = 4. Define total number of schools in Clearwater Bay as M; so M = H + W = 3 + 4 = 7. Answer: 7.


The number of adult owl in Beverly Forest equals 2 plus the number of adult parrot in Beverly Forest. The number of adult parrot in Oakridge Riverside equals 4. The number of adult eagle in Cedar Valley equals 4. The number of adult parrot in Cedar Valley equals 4 plus the sum of the total number of adult animals in Pine Ridge, the total number of adult animals in Oakridge Riverside, and the number of adult parrot in Oakridge Riverside. The number of adult parrot in Beverly Forest equals 3. The number of adult owl in Pine Ridge equals 3. The number of adult eagle in Beverly Forest equals 4 times the sum of the total number of adult animals in Oakridge Riverside, the number of adult owl in Pine Ridge, and the number of adult owl in Oakridge Riverside. The number of adult owl in Cedar Valley equals the number of adult parrot in Beverly Forest. The number of adult owl in Oakridge Riverside equals 2 plus the number of adult owl in Pine Ridge.

Question: How many adult eagle does Beverly Forest have?

Solution: Define adult owl in Pine Ridge as j; so j = 3. Define adult owl in Oakridge Riverside as e; w = j = 3; so e = 2 + w = 2 + 3 = 5. Define adult parrot in Oakridge Riverside as h; so h = 4. Define total number of adult animals in Oakridge Riverside as B; so B = h + e = 4 + 5 = 9. Define adult eagle in Beverly Forest as r; U = B + j = 9 + 3 = 12; t = U + e = 12 + 5 = 17; so r = 4 * t = 4 * 17 = 68. Answer: 68.


The number of adult fox in Oakridge Riverside equals 4 times the sum of the total number of adult animals in Beverly Forest, the number of adult bear in Beverly Forest, and the number of adult deer in Beverly Forest. The number of adult bear in Beverly Forest equals 4. The number of adult deer in Beverly Forest equals 4 times the number of adult bear in Beverly Forest. The number of adult deer in Cedar Valley equals 4. The number of adult fox in Cedar Valley equals 4.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult bear in Beverly Forest as g; so g = 4. Define adult deer in Beverly Forest as Y; S = g = 4; so Y = 4 * S = 4 * 4 = 16. Define total number of adult animals in Beverly Forest as K; so K = g + Y = 4 + 16 = 20. Define adult fox in Oakridge Riverside as G; q = K + g = 20 + 4 = 24; a = q + Y = 24 + 16 = 40; so G = 4 * a = 4 * 40 = 160. Define total number of adult animals in Oakridge Riverside as P; so P = G = 160. Answer: 160.


The number of adult deer in Cedar Valley equals the difference between the total number of adult animals in Beverly Forest and the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 3 times the number of adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals 3. The number of adult fox in Cedar Valley equals the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult fox in Beverly Forest as O; so O = 3. Define adult deer in Beverly Forest as B; f = O = 3; so B = 3 * f = 3 * 3 = 9. Define total number of adult animals in Beverly Forest as t; so t = O + B = 3 + 9 = 12. Define adult fox in Cedar Valley as q; so q = t = 12. Define adult deer in Cedar Valley as s; so s = t - B = 12 - 9 = 3. Define total number of adult animals in Cedar Valley as W; so W = q + s = 12 + 3 = 15. Answer: 15.


The number of regional medical school in Evervale City equals the number of public highschool in Evervale City. The number of public highschool in Brightford equals 1. The number of public highschool in Evervale City equals 2. The number of regional medical school in Brightford equals 1 plus the sum of the total number of schools in Evervale City and the number of public highschool in Evervale City.

Question: What is the total number of schools in Brightford?

Solution: Define public highschool in Evervale City as J; so J = 2. Define regional medical school in Evervale City as M; so M = J = 2. Define total number of schools in Evervale City as V; so V = M + J = 2 + 2 = 4. Define regional medical school in Brightford as w; y = V + J = 4 + 2 = 6; so w = 1 + y = 1 + 6 = 7. Define public highschool in Brightford as W; so W = 1. Define total number of schools in Brightford as R; so R = w + W = 7 + 1 = 8. Answer: 8.


The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals 1 plus the number of solemn period drama in Golden Banana Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals the difference between the total number of movies in Golden Banana Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as T; so T = 4. Define intense detective thriller in Golden Banana Movie Festival as b; u = T = 4; so b = 1 + u = 1 + 4 = 5. Define total number of movies in Golden Banana Movie Festival as y; so y = b + T = 5 + 4 = 9. Define solemn period drama in Verdi Movie Festival as C; so C = y - b = 9 - 5 = 4. Define intense detective thriller in Verdi Movie Festival as I; so I = 4. Define total number of movies in Verdi Movie Festival as v; so v = I + C = 4 + 4 = 8. Answer: 8.


The number of adult owl in Maple Creek equals 2. The number of adult parrot in Pine Ridge equals the number of adult owl in Oakridge Riverside. The number of adult eagle in Pine Ridge equals 2. The number of adult blue jay in Oakridge Riverside equals the number of adult owl in Oakridge Riverside. The number of adult owl in Pine Ridge equals 2. The number of adult crow in Beverly Forest equals 2 times the sum of the number of adult crow in Maple Creek, the number of adult parrot in Beverly Forest, and the number of adult crow in Cedar Valley. The number of adult eagle in Beverly Forest equals the difference between the total number of adult animals in Maple Creek and the number of adult blue jay in Maple Creek. The number of adult crow in Cedar Valley equals the number of adult owl in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 1. The number of adult blue jay in Maple Creek equals 2. The number of adult parrot in Maple Creek equals 1. The number of adult parrot in Beverly Forest equals the difference between the number of adult owl in Oakridge Riverside and the number of adult crow in Cedar Valley. The number of adult eagle in Oakridge Riverside equals the number of adult parrot in Pine Ridge. The number of adult blue jay in Cedar Valley equals the number of adult owl in Pine Ridge. The number of adult owl in Beverly Forest equals the difference between the number of adult parrot in Beverly Forest and the number of adult owl in Oakridge Riverside. The number of adult crow in Maple Creek equals 2 plus the sum of the number of adult parrot in Maple Creek and the number of adult blue jay in Maple Creek.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult parrot in Maple Creek as Q; so Q = 1. Define adult owl in Maple Creek as P; so P = 2. Define adult blue jay in Maple Creek as G; so G = 2. Define adult crow in Maple Creek as h; j = Q + G = 1 + 2 = 3; so h = 2 + j = 2 + 3 = 5. Define total number of adult animals in Maple Creek as v; a = P + G = 2 + 2 = 4; l = a + h = 4 + 5 = 9; so v = l + Q = 9 + 1 = 10. Answer: 10.


The number of culinarian school in Brightford equals the sum of the number of regional medical school in Brightford and the number of regional medical school in Hawkesbury. The number of regional medical school in Brightford equals 4 plus the total number of schools in Hawkesbury. The number of culinarian school in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of regional medical school in Hawkesbury equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define regional medical school in Hawkesbury as Z; so Z = 2. Define culinarian school in Hawkesbury as A; so A = Z = 2. Define total number of schools in Hawkesbury as p; so p = Z + A = 2 + 2 = 4. Define regional medical school in Brightford as T; j = p = 4; so T = 4 + j = 4 + 4 = 8. Define culinarian school in Brightford as Y; so Y = T + Z = 8 + 2 = 10. Define total number of schools in Brightford as d; so d = T + Y = 8 + 10 = 18. Answer: 18.


The number of calm road movie in Cinéma de Montreval equals 4. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the total number of movies in Cinéma de Montreval, and the number of calm road movie in Cinéma de Montreval. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1 plus the sum of the total number of movies in Cinéma de Montreval and the number of calm road movie in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define calm road movie in Cinéma de Montreval as M; so M = 4. Define total number of movies in Cinéma de Montreval as h; so h = M = 4. Define futuristic sci-fi movie in Festival de Saint-Rivage as F; p = h + M = 4 + 4 = 8; so F = 1 + p = 1 + 8 = 9. Define solemn period drama in Festival de Saint-Rivage as t; B = F + h = 9 + 4 = 13; so t = B + M = 13 + 4 = 17. Define total number of movies in Festival de Saint-Rivage as T; so T = F + t = 9 + 17 = 26. Answer: 26.


The number of calm road movie in West Sahara Movie Festival equals 3 plus the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 1 plus the sum of the total number of movies in West Sahara Movie Festival, the number of futuristic sci-fi movie in West Sahara Movie Festival, and the number of calm road movie in West Sahara Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define futuristic sci-fi movie in West Sahara Movie Festival as q; so q = 4. Define calm road movie in West Sahara Movie Festival as o; X = q = 4; so o = 3 + X = 3 + 4 = 7. Define total number of movies in West Sahara Movie Festival as i; so i = q + o = 4 + 7 = 11. Define futuristic sci-fi movie in Golden Banana Movie Festival as V; x = i + q = 11 + 4 = 15; Z = x + o = 15 + 7 = 22; so V = 1 + Z = 1 + 22 = 23. Define total number of movies in Golden Banana Movie Festival as g; so g = V = 23. Answer: 23.


The number of adult fox in Mayer Aquarium equals the total number of adult animals in Bundle Ranch. The number of adult wolf in South Zoo equals 4 plus the number of adult fox in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 4. The number of adult bear in South Zoo equals 4. The number of adult fox in Bundle Ranch equals 4 times the number of adult wolf in Bundle Ranch. The number of adult wolf in Bundle Ranch equals 1. The number of adult bear in Hamilton Farm equals the number of adult wolf in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in Bundle Ranch as V; so V = 1. Define adult fox in Bundle Ranch as g; s = V = 1; so g = 4 * s = 4 * 1 = 4. Define total number of adult animals in Bundle Ranch as r; so r = g + V = 4 + 1 = 5. Define adult fox in Mayer Aquarium as b; so b = r = 5. Define adult wolf in South Zoo as w; i = b = 5; so w = 4 + i = 4 + 5 = 9. Define adult bear in Hamilton Farm as J; so J = w = 9. Define total number of adult animals in Hamilton Farm as k; so k = J = 9. Answer: 9.