The number of calm road movie in Cinéma de Montreval equals 4 times the sum of the total number of movies in Rêves de Belleville, the number of calm road movie in Rêves de Belleville, and the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 2 times the number of calm road movie in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 4.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define calm road movie in Rêves de Belleville as l; so l = 4. Define intense detective thriller in Rêves de Belleville as w; P = l = 4; so w = 2 * P = 2 * 4 = 8. Define total number of movies in Rêves de Belleville as z; so z = w + l = 8 + 4 = 12. Define calm road movie in Cinéma de Montreval as H; y = z + l = 12 + 4 = 16; R = y + w = 16 + 8 = 24; so H = 4 * R = 4 * 24 = 96. Define total number of movies in Cinéma de Montreval as V; so V = H = 96. Answer: 96.


The number of culinarian school in Glenfield City equals 2. The number of regional medical school in Glenfield City equals the sum of the total number of schools in Evervale City, the number of culinarian school in Evervale City, and the number of regional medical school in Evervale City. The number of regional medical school in Evervale City equals 2. The number of culinarian school in Evervale City equals 3.

Question: What is the total number of schools in Glenfield City?

Solution: Define regional medical school in Evervale City as b; so b = 2. Define culinarian school in Evervale City as I; so I = 3. Define total number of schools in Evervale City as f; so f = I + b = 3 + 2 = 5. Define regional medical school in Glenfield City as W; A = f + I = 5 + 3 = 8; so W = A + b = 8 + 2 = 10. Define culinarian school in Glenfield City as m; so m = 2. Define total number of schools in Glenfield City as X; so X = m + W = 2 + 10 = 12. Answer: 12.


The number of adult fox in Pine Ridge equals 3. The number of adult deer in Oakridge Riverside equals the number of adult bear in Oakridge Riverside. The number of adult fox in Beverly Forest equals 1 plus the total number of adult animals in Pine Ridge. The number of adult bear in Oakridge Riverside equals 3 times the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult fox in Pine Ridge as f; so f = 3. Define total number of adult animals in Pine Ridge as t; so t = f = 3. Define adult fox in Beverly Forest as S; E = t = 3; so S = 1 + E = 1 + 3 = 4. Define total number of adult animals in Beverly Forest as j; so j = S = 4. Define adult bear in Oakridge Riverside as n; M = j = 4; so n = 3 * M = 3 * 4 = 12. Define adult deer in Oakridge Riverside as Q; so Q = n = 12. Define total number of adult animals in Oakridge Riverside as D; so D = n + Q = 12 + 12 = 24. Answer: 24.


The number of adult fox in Pine Ridge equals 3 times the number of adult bear in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 4 plus the sum of the total number of adult animals in Pine Ridge, the number of adult bear in Oakridge Riverside, and the number of adult fox in Pine Ridge. The number of adult bear in Oakridge Riverside equals 1.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult bear in Oakridge Riverside as b; so b = 1. Define adult fox in Pine Ridge as o; R = b = 1; so o = 3 * R = 3 * 1 = 3. Define total number of adult animals in Pine Ridge as N; so N = o = 3. Define adult fox in Oakridge Riverside as f; B = N + b = 3 + 1 = 4; n = B + o = 4 + 3 = 7; so f = 4 + n = 4 + 7 = 11. Define total number of adult animals in Oakridge Riverside as V; so V = b + f = 1 + 11 = 12. Answer: 12.


The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of calm road movie in Festival de Clairmont equals 4 plus the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 plus the sum of the total number of movies in Festival de Clairmont, the number of upbeat metropolis comedy in Festival de Clairmont, and the number of calm road movie in Festival de Clairmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as D; so D = 4. Define calm road movie in Festival de Clairmont as l; f = D = 4; so l = 4 + f = 4 + 4 = 8. Define total number of movies in Festival de Clairmont as U; so U = l + D = 8 + 4 = 12. Define upbeat metropolis comedy in Festival de Saint-Rivage as M; H = U + D = 12 + 4 = 16; r = H + l = 16 + 8 = 24; so M = 2 + r = 2 + 24 = 26. Define total number of movies in Festival de Saint-Rivage as w; so w = M = 26. Answer: 26.


The number of culinarian school in Westhaven City equals 4 times the number of private middle school in Westhaven City. The number of private middle school in Westhaven City equals 2. The number of culinarian school in Hawkesbury equals 4 times the sum of the total number of schools in Westhaven City, the number of private middle school in Westhaven City, and the number of culinarian school in Westhaven City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Westhaven City as s; so s = 2. Define culinarian school in Westhaven City as U; X = s = 2; so U = 4 * X = 4 * 2 = 8. Define total number of schools in Westhaven City as d; so d = s + U = 2 + 8 = 10. Define culinarian school in Hawkesbury as F; z = d + s = 10 + 2 = 12; p = z + U = 12 + 8 = 20; so F = 4 * p = 4 * 20 = 80. Define total number of schools in Hawkesbury as a; so a = F = 80. Answer: 80.


The number of adult parrot in Jefferson Circus equals 3 plus the sum of the total number of adult animals in South Zoo, the number of adult owl in South Zoo, and the number of adult parrot in South Zoo. The number of adult owl in South Zoo equals 2. The number of adult parrot in South Zoo equals 4 plus the number of adult owl in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult owl in South Zoo as L; so L = 2. Define adult parrot in South Zoo as g; e = L = 2; so g = 4 + e = 4 + 2 = 6. Define total number of adult animals in South Zoo as R; so R = g + L = 6 + 2 = 8. Define adult parrot in Jefferson Circus as W; n = R + L = 8 + 2 = 10; a = n + g = 10 + 6 = 16; so W = 3 + a = 3 + 16 = 19. Define total number of adult animals in Jefferson Circus as U; so U = W = 19. Answer: 19.


The number of regional medical school in Riverton City equals 2 times the sum of the total number of schools in Clearwater Bay, the number of regional medical school in Clearwater Bay, and the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 4 times the number of regional medical school in Clearwater Bay. The number of private middle school in Shoreline City equals 2 plus the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 4. The number of regional medical school in Shoreline City equals 3.

Question: What is the total number of schools in Riverton City?

Solution: Define regional medical school in Clearwater Bay as c; so c = 4. Define public highschool in Clearwater Bay as R; t = c = 4; so R = 4 * t = 4 * 4 = 16. Define total number of schools in Clearwater Bay as F; so F = c + R = 4 + 16 = 20. Define regional medical school in Riverton City as J; o = F + c = 20 + 4 = 24; d = o + R = 24 + 16 = 40; so J = 2 * d = 2 * 40 = 80. Define total number of schools in Riverton City as w; so w = J = 80. Answer: 80.


The number of calm road movie in Golden Banana Movie Festival equals 4 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 2 plus the sum of the total number of movies in Golden Banana Movie Festival, the number of upbeat metropolis comedy in Golden Banana Movie Festival, and the number of calm road movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of calm road movie in Taylor Movie Festival equals 4 plus the sum of the number of solemn period drama in Northwood Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 1.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define upbeat metropolis comedy in Golden Banana Movie Festival as b; so b = 3. Define calm road movie in Golden Banana Movie Festival as m; z = b = 3; so m = 4 + z = 4 + 3 = 7. Define total number of movies in Golden Banana Movie Festival as g; so g = m + b = 7 + 3 = 10. Define solemn period drama in Northwood Movie Festival as J; r = g + b = 10 + 3 = 13; O = r + m = 13 + 7 = 20; so J = 2 + O = 2 + 20 = 22. Define total number of movies in Northwood Movie Festival as L; so L = J = 22. Answer: 22.


The number of public highschool in Westhaven City equals 4 plus the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 2. The number of public highschool in Brightford equals 2 times the sum of the number of public highschool in Westhaven City and the number of culinarian school in Westhaven City. The number of culinarian school in Brightford equals the difference between the number of public highschool in Westhaven City and the number of culinarian school in Westhaven City.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Westhaven City as F; so F = 2. Define public highschool in Westhaven City as v; R = F = 2; so v = 4 + R = 4 + 2 = 6. Define public highschool in Brightford as p; E = v + F = 6 + 2 = 8; so p = 2 * E = 2 * 8 = 16. Define culinarian school in Brightford as U; so U = v - F = 6 - 2 = 4. Define total number of schools in Brightford as N; so N = p + U = 16 + 4 = 20. Answer: 20.


The number of upbeat metropolis comedy in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1. The number of solemn period drama in Cinéma de Montreval equals 4. The number of upbeat metropolis comedy in Festival de Clairmont equals 1 plus the sum of the total number of movies in Festival de Saint-Rivage, the number of intense detective thriller in Festival de Saint-Rivage, and the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 3 times the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 2.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define intense detective thriller in Festival de Saint-Rivage as W; so W = 2. Define calm road movie in Festival de Saint-Rivage as E; V = W = 2; so E = 3 * V = 3 * 2 = 6. Define total number of movies in Festival de Saint-Rivage as A; so A = W + E = 2 + 6 = 8. Define upbeat metropolis comedy in Festival de Clairmont as j; y = A + W = 8 + 2 = 10; b = y + E = 10 + 6 = 16; so j = 1 + b = 1 + 16 = 17. Define total number of movies in Festival de Clairmont as q; so q = j = 17. Answer: 17.


The number of public highschool in Westhaven City equals the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 4. The number of public highschool in Brightford equals 1. The number of culinarian school in Brightford equals the sum of the total number of schools in Westhaven City, the number of culinarian school in Westhaven City, and the number of public highschool in Westhaven City.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Westhaven City as r; so r = 4. Define public highschool in Westhaven City as u; so u = r = 4. Define total number of schools in Westhaven City as A; so A = u + r = 4 + 4 = 8. Define culinarian school in Brightford as a; p = A + r = 8 + 4 = 12; so a = p + u = 12 + 4 = 16. Define public highschool in Brightford as d; so d = 1. Define total number of schools in Brightford as G; so G = d + a = 1 + 16 = 17. Answer: 17.


The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of upbeat metropolis comedy in Taylor Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival, the number of upbeat metropolis comedy in West Sahara Movie Festival, and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of futuristic sci-fi movie in West Sahara Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define futuristic sci-fi movie in West Sahara Movie Festival as I; so I = 2. Define upbeat metropolis comedy in West Sahara Movie Festival as R; so R = I = 2. Define total number of movies in West Sahara Movie Festival as v; so v = I + R = 2 + 2 = 4. Define futuristic sci-fi movie in Taylor Movie Festival as T; S = v + R = 4 + 2 = 6; so T = S + I = 6 + 2 = 8. Define upbeat metropolis comedy in Taylor Movie Festival as O; so O = T = 8. Define total number of movies in Taylor Movie Festival as t; so t = T + O = 8 + 8 = 16. Answer: 16.


The number of regional medical school in Glenfield City equals 2 plus the number of culinarian school in Glenfield City. The number of culinarian school in Brightford equals 3 times the sum of the total number of schools in Glenfield City, the number of culinarian school in Glenfield City, and the number of regional medical school in Glenfield City. The number of culinarian school in Glenfield City equals 3.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Glenfield City as t; so t = 3. Define regional medical school in Glenfield City as Q; f = t = 3; so Q = 2 + f = 2 + 3 = 5. Define total number of schools in Glenfield City as E; so E = Q + t = 5 + 3 = 8. Define culinarian school in Brightford as Z; M = E + t = 8 + 3 = 11; N = M + Q = 11 + 5 = 16; so Z = 3 * N = 3 * 16 = 48. Define total number of schools in Brightford as l; so l = Z = 48. Answer: 48.


The number of private middle school in Westhaven City equals 2 times the sum of the total number of schools in Evervale City, the number of elementary school in Evervale City, and the number of public highschool in Evervale City. The number of elementary school in Evervale City equals 4. The number of public highschool in Evervale City equals 2 times the number of elementary school in Evervale City.

Question: What is the total number of schools in Westhaven City?

Solution: Define elementary school in Evervale City as P; so P = 4. Define public highschool in Evervale City as l; e = P = 4; so l = 2 * e = 2 * 4 = 8. Define total number of schools in Evervale City as C; so C = l + P = 8 + 4 = 12. Define private middle school in Westhaven City as W; E = C + P = 12 + 4 = 16; t = E + l = 16 + 8 = 24; so W = 2 * t = 2 * 24 = 48. Define total number of schools in Westhaven City as Y; so Y = W = 48. Answer: 48.


The number of adult bear in Mayer Aquarium equals 3. The number of adult fox in Bundle Ranch equals 4 plus the sum of the number of adult bear in Bundle Ranch, the number of adult fox in Mayer Aquarium, and the number of adult bear in Mayer Aquarium. The number of adult bear in Bundle Ranch equals 1 plus the total number of adult animals in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals the number of adult bear in Mayer Aquarium.

Question: How many adult fox does Bundle Ranch have?

Solution: Define adult bear in Mayer Aquarium as T; so T = 3. Define adult fox in Mayer Aquarium as M; so M = T = 3. Define total number of adult animals in Mayer Aquarium as V; so V = M + T = 3 + 3 = 6. Define adult bear in Bundle Ranch as I; G = V = 6; so I = 1 + G = 1 + 6 = 7. Define adult fox in Bundle Ranch as R; g = I + M = 7 + 3 = 10; F = g + T = 10 + 3 = 13; so R = 4 + F = 4 + 13 = 17. Answer: 17.


The number of adult parrot in Cedar Valley equals 4 plus the sum of the total number of adult animals in Oakridge Riverside and the number of adult eagle in Oakridge Riverside. The number of adult eagle in Oakridge Riverside equals 1. The number of adult eagle in Cedar Valley equals 2 plus the difference between the number of adult parrot in Cedar Valley and the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult eagle in Oakridge Riverside as N; so N = 1. Define total number of adult animals in Oakridge Riverside as T; so T = N = 1. Define adult parrot in Cedar Valley as x; S = T + N = 1 + 1 = 2; so x = 4 + S = 4 + 2 = 6. Define adult eagle in Cedar Valley as Y; m = x - T = 6 - 1 = 5; so Y = 2 + m = 2 + 5 = 7. Define total number of adult animals in Cedar Valley as B; so B = x + Y = 6 + 7 = 13. Answer: 13.