Programmatically generate if elif elif elif else
<p>I would like to condense some wet code that looks like this:</p>

<pre><code>if slips[i] &lt; 3000:
    ac.setBackgroundColor(wheel['slip'], 0, 0, 0)
    # setBackgroundOpacity deliberately omitted here
elif slips[i] &lt; 3700:
    ac.setBackgroundColor(wheel['slip'], .2, .4, .2)
    ac.setBackgroundOpacity(wheel['slip'], 1)
elif slips[i] &lt; 4100:
    ac.setBackgroundColor(wheel['slip'], 0, 1, 0)
    ac.setBackgroundOpacity(wheel['slip'], 1)
elif slips[i] &lt; 4500:
    ac.setBackgroundColor(wheel['slip'], 0, 0, 1)
    ac.setBackgroundOpacity(wheel['slip'], 1)
else:
    ac.setBackgroundColor(wheel['slip'], 1, 0, 0)
    ac.setBackgroundOpacity(wheel['slip'], 1)
</code></pre>

<p>Each time this snippet of code is repeated, the only things that change are the background canvas (<code>wheel['slip']</code> in this case), and the numbers in the if elif else's.</p>

<p>My first thought to dry this up was to make something that could be used like this:</p>

<pre><code>if_replacer(wheel['slip'], slips[i], 3000, 3700, 4100, 4500)

def if_replacer(canvas, value, *args):
    # idunno
</code></pre>

<p>My question is, how would I programmatically generate the if elif else's? I know I could hard-code it like so:</p>

<pre><code>def if_replacer(canvas, value, c1, c2, c3, c4):
    if value &lt; c1:
        ac.setBackgroundColor(canvas, 0, 0, 0)
        return
    elif value &lt; c2:
        ac.setBackgroundColor(canvas, .2, .4, .2)
    elif value &lt; c3:
        ac.setBackgroundColor(canvas, 0, 1, 0)
    elif value &lt; c4:
        ac.setBackgroundColor(canvas, 0, 0, 1)
    else:
        ac.setBackgroundColor(canvas, 1, 0, 0)
    ac.setBackgroundOpacity(canvas, 1)
</code></pre>

<p>But I'm interested if there is a succinct and Pythonic method to accomplish this.</p>

<p>edit: A lot of excellent answers, but alas I can only mark one of them as accepted (though all valid solutions were upvoted). I accepted the answer that I implemented in my code, but for anyone else who stumbles across this question, do take a look at the other solutions, they're all excellent. And, thanks to everyone who wrote an answer.</p>

<p>Here's one possible solution.</p>

<pre><code>def least_bound_index(value, bounds):
    """return the least index such that value &lt; bounds[i], or else len(bounds)""" 
    for i, b in enumerate(bounds):
        if value &lt; b:
            return i
    return i+1

bounds = [3000, 3700, 4100, 4500]
bgcolors = [(0, 0, 0), (.2, .4, .2), (0, 1, 0), (0, 0, 1), (1, 0, 0)]

i = least_bound_index(slips[i], bounds)
ac.setBackgroundColor(wheel['slip'], *bgcolors[i])
if i &gt; 0:
    ac.setBackgroundOpacity(wheel['slip'], 1)
</code></pre>

<p>Note that <code>least_bound_index</code> could also be called <code>index_between</code> because you could imagine [a, b, c, d] on a number line, and it would tell you where the value lands out of these choices:</p>

<pre><code>  a   b   c   d
^   ^   ^   ^   ^
0   1   2   3   4
</code></pre>

python if-statement dry