How to real-time check the django view operating process
<p>Here is the thing, When I submit a form from template to view ,since the process of this view will cost a lot time. I don's think our user enjoy to wait.
So, I want to this: when user click the submit button,the browser will redirect to a new page or just show a sub-page in the same window that can print the real-time executing information.</p>

<p>Before I post this question, I did a little research, looks like the celery can do this thing, am I right? If there is same problem already be asked in stackoverflow ,PLZ give me the link.</p>

<p>Thank for your time!</p>

<p>(English is not my mother language, so I don't know if we have any term to describe this function,if we do,PLZ give me a hint )</p>

<p><a href="https://channels.readthedocs.io/en/latest/" rel="nofollow">django-channels</a> could be a good solution to send information as they execute on the server side in this way you can send information on the client side by opening a websocket.  </p>

<p>Channel can be used to post data to the client side without having to wait for the HttpResponse. </p>

<p>Heroku has nice <a href="https://blog.heroku.com/in_deep_with_django_channels_the_future_of_real_time_apps_in_django" rel="nofollow">post</a> explaning channels.</p>

<p>Hope this helps.</p>

python django celery