Logical operations with array of strings in Python
<p>I know the following logical operation works with numpy: </p>

<pre><code>A = np.array([True, False, True])
B = np.array([1.0, 2.0, 3.0])
C = A*B = array([1.0, 0.0, 3.0])
</code></pre>

<p>But the same isn't true if B is an array of strings. Is it possible to do the following:   </p>

<pre><code>A = np.array([True, False, True])
B = np.array(['eggs', 'milk', 'cheese'])
C = A*B = array(['eggs', '', 'cheese'])
</code></pre>

<p>That is a string multiplied with False should equal an empty string. Can this be done without a loop in Python (doesn't have to use numpy)?</p>

<p>Thanks!</p>

<p>Since strings may be multiplied by integers, and booleans are integers:</p>

<pre><code>A = [True, False, True]
B = ['eggs', 'milk', 'cheese']
C = [a*b for a, b in zip(A, B)]
# C = ['eggs', '', 'cheese']
</code></pre>

<p>I still uses some kind of loop (same as numpy solution), but it's hidden in concise list comprehension.</p>

<p>Alternatively:</p>

<pre><code>C = [a if b else '' for a, b in zip(A, B)]  # explicit loop may be clearer than multiply-sequence trick
</code></pre>

python string numpy logical-operators