Python for Data Analysis error: Expecting value: line 1 column 1 (char 0)
<p>I am following along the examples of Python for Data Analysis and the first examples shows:</p>

<pre><code>In [15]: path = 'ch02/usagov_bitly_data2012-03-16-1331923249.txt'
In [16]: open(path).readline()
Out[16]: '{ "a": "Mozilla\\/5.0 (Windows NT 6.1; WOW64) AppleWebKit\\/535.11
(KHTML, like Gecko) Chrome\\/17.0.963.78 Safari\\/535.11", "c": "US", "nk": 1,
"tz": "America\\/New_York", "gr": "MA", "g": "A6qOVH", "h": "wfLQtf", "l":
"orofrog", "al": "en-US,en;q=0.8", "hh": "1.usa.gov", "r":
"http:\\/\\/www.facebook.com\\/l\\/7AQEFzjSi\\/1.usa.gov\\/wfLQtf", "u":
"http:\\/\\/www.ncbi.nlm.nih.gov\\/pubmed\\/22415991", "t": 1331923247, "hc":
1331822918, "cy": "Danvers", "ll": [ 42.576698, -70.954903 ] }\n'
</code></pre>

<p>After following these instructions I get:</p>

<pre><code>In [21]: open(path).readline()
Out[21]: 'Ã¯Â»Â¿{ "a": "Mozilla\\/5.0 (Windows NT 6.1; WOW64) AppleWebKit\\/535.11
(KHTML, like Gecko) Chrome\\/17.0.963.78 Safari\\/535.11", "c": "US", "nk": 1, "
tz": "America\\/New_York", "gr": "MA", "g": "A6qOVH", "h": "wfLQtf", "l": "orofr
og", "al": "en-US,en;q=0.8", "hh": "1.usa.gov", "r": "http:\\/\\/www.facebook.co
m\\/l\\/7AQEFzjSi\\/1.usa.gov\\/wfLQtf", "u": "http:\\/\\/www.ncbi.nlm.nih.gov\\
/pubmed\\/22415991", "t": 1331923247, "hc": 1331822918, "cy": "Danvers", "ll": [
 42.576698, -70.954903 ] }\n'
</code></pre>

<p>The only difference from the book is the "Ã¯Â»Â¿" part. </p>

<p>Later, when I try:</p>

<pre><code>import json
path = 'ch02/usagov_bitly_data2012-03-16-1331923249.txt'
records = [json.loads(line) for line in open(path)]
</code></pre>

<p>... what I get is:</p>

<pre><code>`In [22]: import json

In [23]: path = 'usagov_bitly_data2012-03-16-1331923249.txt'

In [24]: records = [json.loads(line) for line in open(path)]
---------------------------------------------------------------------------
JSONDecodeError                           Traceback (most recent call last)
&lt;ipython-input-24-b1e0b494454a&gt; in &lt;module&gt;()
----&gt; 1 records = [json.loads(line) for line in open(path)]

&lt;ipython-input-24-b1e0b494454a&gt; in &lt;listcomp&gt;(.0)
----&gt; 1 records = [json.loads(line) for line in open(path)]

C:\Anaconda3\lib\json\__init__.py in loads(s, encoding, cls, object_hook, parse_
float, parse_int, parse_constant, object_pairs_hook, **kw)
    317             parse_int is None and parse_float is None and
    318             parse_constant is None and object_pairs_hook is None and not
 kw):
--&gt; 319         return _default_decoder.decode(s)
    320     if cls is None:
    321         cls = JSONDecoder

C:\Anaconda3\lib\json\decoder.py in decode(self, s, _w)
    337
    338         """
--&gt; 339         obj, end = self.raw_decode(s, idx=_w(s, 0).end())
    340         end = _w(s, end).end()
    341         if end != len(s):

C:\Anaconda3\lib\json\decoder.py in raw_decode(self, s, idx)
    355             obj, end = self.scan_once(s, idx)
    356         except StopIteration as err:
--&gt; 357             raise JSONDecodeError("Expecting value", s, err.value) from
None
    358         return obj, end


JSONDecodeError: Expecting value: line 1 column 1 (char 0)`
</code></pre>

<p>Does any one know why I get this JSONDecodeError error?</p>

<p>Sir, Ã¯Â»Â¿, It is not JSON format, I think that you should remove anomaly text 'Ã¯Â»Â¿' or try some online format JSON to be more clear.</p>

python data-analysis