Python regex replacing \u2022
<p>This is my string:</p>

<pre><code>raw_list = u'Software Engineer with a huge passion for new and innovative products. Experienced gained from working in both big and fast-growing start-ups.  Specialties \u2022 Languages and Frameworks: JavaScript (Nodejs, React), Android, Ruby on Rails 4, iOS (Swift) \u2022 Databases: Mongodb, Postgresql, MySQL, Redis \u2022 Testing Frameworks: Mocha, Rspec xxxx Others: Sphinx, MemCached, Chef.'
</code></pre>

<p>I'm trying to replace the <code>\u2022</code> with just a space.</p>

<pre><code>x=re.sub(r'\u2022', ' ', raw_list)
</code></pre>

<p>But it's not working. What am I doing wrong?</p>

<p>This is my approach, changing regex pattern, you might try</p>

<pre><code>re.sub(r'[^\x00-\x7F]+','',raw_list)
</code></pre>

<blockquote>
  <p>Out[1]: u'Software Engineer with a huge passion for new and
  innovative products. Experienced gained from working in both big and
  fast-growing start-ups.  Specialties  Languages and Frameworks:
  JavaScript (Nodejs, React), Android, Ruby on Rails 4, iOS (Swift) 
  Databases: Mongodb, Postgresql, MySQL, Redis  Testing Frameworks:
  Mocha, Rspec xxxx Others: Sphinx, MemCached, Chef.'</p>
</blockquote>

python regex