sqlalchemy.exc.ProgrammingError: (psycopg2.ProgrammingError) relation "story" does not exist
<p>So this is my code below. I'm trying to create a database, with one story table. The input comes from the html input part</p>

<pre><code>from flask import Flask, render_template
from flask_sqlalchemy import SQLAlchemy
from flask import request, redirect, url_for

app = Flask(__name__)
password = input("Your database password: ")
app.config['SQLALCHEMY_DATABASE_URI'] = 'postgresql://adambodnar:{}@localhost/user_stories'.format(password)
db = SQLAlchemy(app)

class Story(db.Model):
   id = db.Column(db.Integer, primary_key=True)
   story_title = db.Column(db.String(80), unique=True)
   user_story = db.Column(db.Text)
   acceptance_criteria = db.Column(db.Text)
   business_value = db.Column(db.Integer)
   estimation = db.Column(db.Integer)
   status = db.Column(db.String(30))

   def __init__(self, story_title, user_story, acceptance_criteria, business_value, estimation, status):
        self.story_title = story_title
        self.user_story = user_story
        self.acceptance_criteria = acceptance_criteria
        self.business_value = business_value
        self.estimation = estimation
        self.status = status


@app.route('/')
def index():
    return render_template('form.html')


@app.route('/story', methods=['POST'])
def story_post():
    new_story = Story(request.form['story_title'],request.form['user_story'], request.form['acceptance_criteria'], request.form['business_value'], request.form['estimation'], request.form['status'])


    db.session.add(new_story)
    db.session.commit()
    return redirect(url_for('index'))

if __name__ == '__main__':
    app.run(host='0.0.0.0', port=8000)
</code></pre>

<p>when I try to run this, I get the following error:</p>

<pre><code>sqlalchemy.exc.ProgrammingError: (psycopg2.ProgrammingError) relation "story" does not exist
LINE 1: INSERT INTO story (story_title, user_story, acceptance_crite...
                ^
 [SQL: 'INSERT INTO story (story_title, user_story, acceptance_criteria, business_value, estimation, status) VALUES (%(story_title)s, %(user_story)s, %(acceptance_criteria)s, %(business_value)s, %(estimation)s, %(status)s) RETURNING story.id'] [parameters: {'acceptance_criteria': 'asdasd', 'estimation': '1', 'user_story': 'asd', 'status': 'Planning', 'story_title': 'asd', 'business_value': '100'}]
</code></pre>

<p>The story table is not even created, I checked it through pgAdmin. I've tried a lot of things, some questions suggested to drop the table, but it's not created</p>

<p>Have you followed the <a href="http://flask-sqlalchemy.pocoo.org/2.1/quickstart/" rel="nofollow">quickstart guide</a> for Flask and sqlalchemy?  Anyway, on the guide you will notice that it says to do this:</p>

<blockquote>
  <p>To create the initial database, just import the db object from an
  interactive Python shell and run the SQLAlchemy.create_all() method to
  create the tables and database:</p>

<pre><code>&gt;&gt;&gt; from yourapplication import db
&gt;&gt;&gt; db.create_all()
</code></pre>
</blockquote>

<p>In the code you included with your question the table creation code seems to be missing, which explains the table not being created.</p>

<p>You can consider including <code>db.create_all()</code> with your application (put it right after <code>db = SqlAlchemy(app)</code>) - if this wrapper functions like the standard sqlalchemy version it should only create new tables and not blow up if tables already exist.</p>

python flask flask-sqlalchemy